hermiene.net

Added an Elastomania section to the index page. This has since been offloaded to the Random page.

Nice car, right? Not in MSIE 6.0. If you're using MSIE 6.0 you should see big, ugly chunks of silver pixels. Those silver pixels should be transparent. Why is MSIE always slacking behind? I don't know, but I hope they can provide full PNG support soon. I want my 24-bit alpha transparent PNG images now, damn it! (Hidden message: Use Opera.)

Added a bunch of Futurama quotes and one from Håvard Torsnes.

Added the XHTML Commandments to the navigation bar. Now deceased.

I've made the Glossary page where I try to gather all the abbreviations I use. For your convenience.

Added the Test Page to the navigation bar.

I found a very cool math problem in my math book today. It looks scary, but it's not. I use the quadratic formula in there, so check my Graphs & Functions page for a refresher, if you need it.

$$(x^2 + 3x)(\sqrt{x + 1} - 4) = 0$$

Find values of \(x\).

First of all, let's figure out what \(x\) can't be. We know that it's illegal to take the square root of a negative number, so \(x > -1\). As you can see, there are two factors in this equation, and they equal \(0\), which means that one of them (or both) have to be zero. So we check them both:

$$\begin{align*}x^2 &+ 3x \\ x_1 &= 0 \\ x_2 &= -3\end{align*}$$

\(-3\) is a false answer, since \(x\) has to be greater than \(-1\). We check the second factor:

$$\begin{align*}\sqrt{x + 1} - 4 &= 0\\ \sqrt{x + 1} &= 4 \\ x + 1 &= 16 \\ x &= 15\end{align*}$$

Now we just have to insert the two values \(0\) and \(15\) into the original equation, and see which of them yields \(0\) as an answer. You can do that for yourself. :-)

Added some quotes to the Quotes page.